Algebra.Com's Answer #546439 by richwmiller(17219)  You can put this solution on YOUR website! Not even close as you know! \n" );
document.write( "What happened to using d=sqrt(x2-x1)^2+(y2-y1)^2 \n" );
document.write( " (-2,2) and point (2,-3) \n" );
document.write( "(-2,2)(2,-3) \n" );
document.write( "d=sqrt((x2-x1)^2)+(y2-y1)^2) \n" );
document.write( "d=sqrt(+(2--2)^2)+(-3-2)^2 \n" );
document.write( "d=sqrt(+(4)^2)+(-5)^2 \n" );
document.write( "d=sqrt(16+25) \n" );
document.write( "d=sqrt(41) \n" );
document.write( "6.40312424 \n" );
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document.write( " Solved by pluggable solver: Distance Formula | \n" );
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document.write( " The first point is (x1,y1). The second point is (x2,y2) \n" );
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document.write( " Since the first point is (-2, 2), we can say (x1, y1) = (-2, 2) \n" );
document.write( " So ,  \n" );
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document.write( " Since the second point is (2, -3), we can also say (x2, y2) = (2, -3) \n" );
document.write( " So ,  \n" );
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document.write( " Put this all together to get: , , , and  \n" );
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document.write( " Now use the distance formula to find the distance between the two points (-2, 2) and (2, -3) \n" );
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document.write( " Plug in , , , and  \n" );
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document.write( " ========================================================== \n" );
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document.write( " Answer: \n" );
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document.write( " The distance between the two points (-2, 2) and (2, -3) is exactly units \n" );
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document.write( " The approximate distance between the two points is about 6.40312423743285 units \n" );
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document.write( " So again, \n" );
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document.write( " Exact Distance: units \n" );
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document.write( " Approximate Distance: units \n" );
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