document.write( "Question 901078: find two consecutive odd integers such that three times the smaller exceeds tow time the larger by 7 \n" ); document.write( "
Algebra.Com's Answer #546437 by JulietG(1812)\"\" \"About 
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A = B+2 (consecutive odd)
\n" ); document.write( "3B = 2A+7
\n" ); document.write( "Substitute the known value of A from the first equation into the second.
\n" ); document.write( "3B = 2A+7
\n" ); document.write( "3B = 2(B+2) + 7
\n" ); document.write( "Distribute
\n" ); document.write( "3B = 2B+4 + 7
\n" ); document.write( "3B = 2B + 11
\n" ); document.write( "Subtract 2B from each side
\n" ); document.write( "B = 11
\n" ); document.write( "If B is 11, then A is 13.

\n" ); document.write( "Prove: three times the smaller exceeds tow time the larger by 7
\n" ); document.write( "3 * 11 = (2*13)+7
\n" ); document.write( "33 = 26+7
\n" ); document.write( "33=33
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