document.write( "Question 901078: find two consecutive odd integers such that three times the smaller exceeds tow time the larger by 7 \n" ); document.write( "
Algebra.Com's Answer #546437 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! A = B+2 (consecutive odd) \n" ); document.write( "3B = 2A+7 \n" ); document.write( "Substitute the known value of A from the first equation into the second. \n" ); document.write( "3B = 2A+7 \n" ); document.write( "3B = 2(B+2) + 7 \n" ); document.write( "Distribute \n" ); document.write( "3B = 2B+4 + 7 \n" ); document.write( "3B = 2B + 11 \n" ); document.write( "Subtract 2B from each side \n" ); document.write( "B = 11 \n" ); document.write( "If B is 11, then A is 13. \n" ); document.write( "Prove: three times the smaller exceeds tow time the larger by 7 \n" ); document.write( "3 * 11 = (2*13)+7 \n" ); document.write( "33 = 26+7 \n" ); document.write( "33=33 \n" ); document.write( " |