document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=901042>Question 901042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In this function, f(x)= -2(x-1)²(x+3) :\r<BR>\n" );
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document.write( "- f(x) touches the x-axis at ?<BR>\n" );
document.write( "- f(x) crosses the x-axis at ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546426 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546426\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The zeros are also critical values.  Check the sign of each interval.\r<BR>\n" );
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document.write( "The zeros are 1 and -3.  You can see this because f is shown in its factored form.  The intervals on x to check signs for f are:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-infinity%3Cx%3C-3 ALIGN=MIDDLE  ALT=\"-infinity%3Cx%3C-3\"   DISABLED_style= \"max-width:90%; height:auto;\" >;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%3Cx%3C1 ALIGN=MIDDLE  ALT=\"-3%3Cx%3C1\"   DISABLED_style= \"max-width:90%; height:auto;\" >;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%3Cx%3Cinfinity ALIGN=MIDDLE  ALT=\"1%3Cx%3Cinfinity\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Pick ANY value in each interval and test the sign of f(x).\r<BR>\n" );
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document.write( "You should find, according to each listed interval:<BR>\n" );
document.write( "Positive, negative, negative.\r<BR>\n" );
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document.write( "Can you conclude what that means?  Note that around the value x=1, the value for f is still negative.  Sign did not change there.\r<BR>\n" );
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