document.write( "Question 901051: F = 1.3481481481481...
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document.write( "1000 F = 1348.1481481481481...
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document.write( "999 F = 1346.8000000000000...
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document.write( "= 1346.8 = 6734/5,
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document.write( "F = 6734/(5*999) = 6734/4995 = 182/135\r
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document.write( "Hello, the above was an example I was studying, an example of how to convert a repeating decimal into a fraction. I understand it! I understand reducing the answer using primes etc BUT What I am NOT understanding Specifically is why 1346.8 = 6734 divided by 5 and why that is divided by 5 multiplied by 999
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document.write( "and can you tell me or elaborate on what technique or property is being used. Thank you \n" );
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Algebra.Com's Answer #546413 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! F = 1.3481481481481... \n" ); document.write( "1000F = 1348.1481481... \n" ); document.write( "- 1F = - 1.3481481... \n" ); document.write( "999F = 1346.8 \n" ); document.write( "F = 1346.8/999 \n" ); document.write( "Multiply by something to get integers. \n" ); document.write( "You can use 10 \n" ); document.write( "F = 13468/9990 \n" ); document.write( "Then reduce \n" ); document.write( "F = 182/135 \n" ); document.write( " \n" ); document.write( " |