document.write( "Question 76101: find the possible values for s in the inequality 12s-20<50-3s-25. \n" ); document.write( "
Algebra.Com's Answer #54641 by wodkit02(9)\"\" \"About 
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To solve this, pretend at first that the < sign is an = sign.\r
\n" ); document.write( "\n" ); document.write( "12s-20 < 50-3s-25 ..... 12s-20 = 50-3s-25\r
\n" ); document.write( "\n" ); document.write( "Now collect all s terms on one side of the equation, and get everything else on the opposite side:
\n" ); document.write( "12s-20 = 50-3s-25
\n" ); document.write( "12s-20+3s = 50-3s+3s-25
\n" ); document.write( "15s-20 = 25
\n" ); document.write( "15s-20+20 = 25+20
\n" ); document.write( "15s = 45\r
\n" ); document.write( "\n" ); document.write( "Solving for s, we get s = 3.\r
\n" ); document.write( "\n" ); document.write( "Now, put the < back in where the = is to get s < 3.\r
\n" ); document.write( "\n" ); document.write( "Let's test this answer:
\n" ); document.write( "1 < 3, so put 1 in for s in the ORIGINAL equation \r
\n" ); document.write( "\n" ); document.write( "12(1)-20 < 25-3(1)
\n" ); document.write( "12-20 < 25-3
\n" ); document.write( "-8 < 22\r
\n" ); document.write( "\n" ); document.write( "Since this is a true statement, we know that values below 3 work.\r
\n" ); document.write( "\n" ); document.write( "Let's test a point greater than 3. If the 12s-20 > 25-3s, then s < 3 solves the original inequality.\r
\n" ); document.write( "\n" ); document.write( "4 > 3\r
\n" ); document.write( "\n" ); document.write( "12(4)-20 < 25-3(4)
\n" ); document.write( "48-20 < 25-12
\n" ); document.write( "28 is NOT < 13, so the all values for s must be less than 3.
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