document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=901035>Question 901035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> together a bottle and a cork cost a dollar and five cents. the bottle cost a dollar more than the cork. use trial and error to determine the cost of the cork </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546408 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You *could* use trial and error, guessing what the number is and plugging it in until you get the right answer, or you could use math :-)<BR>\n" );
document.write( "B + C = 1.05<BR>\n" );
document.write( "B = C + 1.00<BR>\n" );
document.write( "Substitute the value of B from the second equation into the first.<BR>\n" );
document.write( "B + C = $1.05<BR>\n" );
document.write( "(C+1.00)+ C = $1.05<BR>\n" );
document.write( "2C + 1.00 = $1.05<BR>\n" );
document.write( "Subtract a dollar from each side<BR>\n" );
document.write( "2C = .05<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "C = .025<BR>\n" );
document.write( "Each cork costs 2.5 cents.  The bottle costs a dollar more than that, or one dollar and 2.5 cents.<BR>\n" );
document.write( ".025 + 1.025 = $1.05<BR>\n" );
document.write( "That might be a difficult one for trial and error since it contains a half cent. </SPAN>\n" );
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