document.write( "Question 75996This question is from textbook
\n" ); document.write( ": A 14-yard fishing line is cut into two pieces. Three times the length of the longer piece is four times the length of the shorter piece. Find the length of each piece. \n" ); document.write( "
Algebra.Com's Answer #54635 by ptaylor(2198)\"\" \"About 
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Let x=length of shorter piece
\n" ); document.write( "And y=longer piece\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:
\n" ); document.write( "x+y=14-----------------------------------eq 1\r
\n" ); document.write( "\n" ); document.write( "We are also told that:
\n" ); document.write( "3y=4x---------------------------------------eq 2\r
\n" ); document.write( "\n" ); document.write( "divide both sides of eq 2 by 3 and we get:
\n" ); document.write( "y=(4/3)x---substitute this into eq 1:\r
\n" ); document.write( "\n" ); document.write( "x+(4/3)x=14 or
\n" ); document.write( "(7/3)x=14 multiply both sides by 3
\n" ); document.write( "7x=42 divide both sides by 7\r
\n" ); document.write( "\n" ); document.write( "x=6 yards------------------------------shorter piece\r
\n" ); document.write( "\n" ); document.write( "Substitute x=6 into eq 1:
\n" ); document.write( "6+y=14 subtract 6 from both sides
\n" ); document.write( "y=8 yards----------------------------------longer piece\r
\n" ); document.write( "\n" ); document.write( "Ck\r
\n" ); document.write( "\n" ); document.write( "6+8=14
\n" ); document.write( "14=14
\n" ); document.write( "and
\n" ); document.write( "3 times longer = 4 times shorter or
\n" ); document.write( "3*8=4*6
\n" ); document.write( "24=24\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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