document.write( "Question 900956: A part of $7000 was invested at 4% annual interest and remaining at 9% annual interest. At the end of the year the total amount recieved was $7292. How much money was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #546347 by richwmiller(17219)\"\" \"About 
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In the future do not submit similar problems.
\n" ); document.write( "Similar means they are the same type problem but differ by the numbers or addition vs subtraction.
\n" ); document.write( "x+y=7000,
\n" ); document.write( "0.04*x+0.09*y=292
\n" ); document.write( "x=7000-y
\n" ); document.write( "0.04*(7000-y)+0.09*y=292
\n" ); document.write( "280-0.04y+0.09*y=292
\n" ); document.write( "0.05*y=12
\n" ); document.write( "y=240 at 9%
\n" ); document.write( "x=7000-y
\n" ); document.write( "x=6760 at 4%
\n" ); document.write( "check
\n" ); document.write( "0.04*6760+0.09*240=292
\n" ); document.write( "270.4+21.6=292
\n" ); document.write( "292=292
\n" ); document.write( "ok\r
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