document.write( "Question 900956: A part of $7000 was invested at 4% annual interest and remaining at 9% annual interest. At the end of the year the total amount recieved was $7292. How much money was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #546347 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! In the future do not submit similar problems. \n" ); document.write( "Similar means they are the same type problem but differ by the numbers or addition vs subtraction. \n" ); document.write( "x+y=7000, \n" ); document.write( "0.04*x+0.09*y=292 \n" ); document.write( "x=7000-y \n" ); document.write( "0.04*(7000-y)+0.09*y=292 \n" ); document.write( "280-0.04y+0.09*y=292 \n" ); document.write( "0.05*y=12 \n" ); document.write( "y=240 at 9% \n" ); document.write( "x=7000-y \n" ); document.write( "x=6760 at 4% \n" ); document.write( "check \n" ); document.write( "0.04*6760+0.09*240=292 \n" ); document.write( "270.4+21.6=292 \n" ); document.write( "292=292 \n" ); document.write( "ok\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |