document.write( "Question 76095: I really need the solution\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "(5/y-3) - (30 /y^2-9) = 1 \n" );
document.write( "
Algebra.Com's Answer #54632 by bucky(2189) ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( "The denominator \n" ); document.write( "factoring the difference between two squares is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Applying this rule to \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Substituting this into the equation changes the equation to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You can get all the terms over the common denominator of \n" ); document.write( "first term by \n" ); document.write( "the numerator of this multiplier is the same as the denominator. When you do this \n" ); document.write( "multiplication the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then multiply the 1 on the right side by \n" ); document.write( "results in: \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now you can multiply the entire equation (both sides, all terms) by the common denominator \n" ); document.write( " \n" ); document.write( "of all the terms in the equation. The result is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Multiply where called for and the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Subtract \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Rearrange terms in descending powers of y: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Combine the constants: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Multiply the entire equation (both sides and all terms) by -1 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This factors to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "If either of the factors equals zero, then the equation is true because a multiplication \n" ); document.write( "by zero on the left side, makes the entire left side equal to the zero on the right side. \n" ); document.write( "Find the solutions for y by setting each of the factors equal to zero and solving for \n" ); document.write( "y ... \n" ); document.write( ". \n" ); document.write( "y - 2 = 0 <---- add 2 to both sides \n" ); document.write( ". \n" ); document.write( "y = +2 <--- one answer for y \n" ); document.write( ". \n" ); document.write( "y - 3 = 0 <--- add 3 to both sides \n" ); document.write( ". \n" ); document.write( "y = +3 <--- the second answer for y \n" ); document.write( ". \n" ); document.write( "But the second answer [y = +3] is not permitted because this would cause a division by \n" ); document.write( "zero in the second term of the original equation ... the denominator of the second term \n" ); document.write( "is \n" ); document.write( "+3 then one of the factors in the denominator is zero ... and division by zero is not \n" ); document.write( "permitted. \n" ); document.write( ". \n" ); document.write( "So there you are ... the answer to the equation is y = +2. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem a little better. \n" ); document.write( " |