document.write( "Question 10266: First of all, I would like to take this opportunity to thank you for taking the time to answer my question. Here it goes:
\n" ); document.write( "In class, we are studying how to solve systems of linear equations using substitution. The answer key I was given said that this question was supposed to have the solution set of {(-10,2)} The answer I figured out was {(70,-82})
\n" ); document.write( "The question was 3x+2y= -34
\n" ); document.write( " y-x= 12
\n" ); document.write( "I would really appreciate a reply, for I would like to know how to do it before we get to the next step of solving linear equations. Thank you again for your reply on this matter.
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Algebra.Com's Answer #5463 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Use the second equation to solve for y by adding x to each side:
\n" ); document.write( "y-x = 12
\n" ); document.write( "y=x+ 12\r
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\n" ); document.write( "\n" ); document.write( "Now substitute into the first equation:
\n" ); document.write( "3x + 2y = -34
\n" ); document.write( "3x + 2(_______) = -34
\n" ); document.write( "3x + 2(x+ 12)= -34
\n" ); document.write( "3x + 2x + 24 = -34
\n" ); document.write( "5x +24 - 24 = -34 - 24
\n" ); document.write( "5x = -58
\n" ); document.write( "x= -58/5\r
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\n" ); document.write( "\n" ); document.write( "I think maybe you copied the problem wrong. Better take another look. I think the second equation was supposed to be 3x-2y = -34. If this is the case, then the answer in the solution was correct, and you made an error.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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