document.write( "Question 900858: A student drove a distance of 120 miles at an average speed of 55 mph. How much faster would she have to drive on the return trip to save 30 minutes of driving time? \n" ); document.write( "
Algebra.Com's Answer #546235 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 55t=120, \n" ); document.write( "x(t-1/2)=120 \n" ); document.write( "t=120/55 \n" ); document.write( "t=24/11=48/22 \n" ); document.write( "x(48/22-11/22)=120 \n" ); document.write( "x*37/22=120 \n" ); document.write( "37x=2640 \n" ); document.write( "x=71.35\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |