document.write( "Question 900801: find the dimension and maximum area of a rectangle if its perimeter is 36m. \n" ); document.write( "
Algebra.Com's Answer #546152 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Let L and W be the length and width of the rectangle.
\n" ); document.write( "The perimeter is,
\n" ); document.write( "\"P=2L%2B2W=36\"
\n" ); document.write( "So,
\n" ); document.write( "\"L%2BW=36\"
\n" ); document.write( "The area of the rectangle is,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "From the perimeter,
\n" ); document.write( "\"L=36-W\"
\n" ); document.write( "Substitute,
\n" ); document.write( "\"A=%2836-W%29W=36W-W%5E2\"
\n" ); document.write( "To find the extremum, set the derivative of A equal to zero.
\n" ); document.write( "\"dA%2FdW=36-2W\"
\n" ); document.write( "\"36-2W=0\"
\n" ); document.write( "\"2W=36\"
\n" ); document.write( "\"W=18\"
\n" ); document.write( "So then,
\n" ); document.write( "\"L%2B18=36\"
\n" ); document.write( "\"L=18\"
\n" ); document.write( "The maximum area for a given perimeter is actually a square.
\n" ); document.write( "\"A%5Bmax%5D=18%5E2=324\"\"m%5E2\"
\n" ); document.write( "
\n" );