document.write( "Question 900786: A chemist needs 130 mL of a 28% solution but has only 18% and 83% solutions available. Find how many mL of each solution should be mixed to get the desired solution.
\n" ); document.write( "The answer is 110mL of 18%: 20mL of 83%
\n" ); document.write( "I don't know how to set it up. \n" ); document.write( "

Algebra.Com's Answer #546151 by MathTherapy(10552) $\"\"$ $\"About$

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A chemist needs 130 mL of a 28% solution but has only 18% and 83% solutions available. Find how many mL of each solution should be mixed to get the desired solution.
\n" ); document.write( "The answer is 110mL of 18%: 20mL of 83%
\n" ); document.write( "I don't know how to set it up.
\n" ); document.write( "


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document.write( "Let amount of 18% solution to be mixed, be E
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document.write( "Then amount of 83% solution to be mixed = 130 - E
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document.write( "Therefore, .18E + .83(130 – E) = .28(130)
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document.write( ".18E + 107.9 - .83E = 36.4
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document.write( ".18E - .83E = 36.4 – 107.9 
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document.write( "- .65S = - 71.5
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document.write( "E, or amount of 18% solution = , or  mL
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document.write( "Amount of 83% solution to be mixed: 130 – 110, or  mL \n" );
document.write( "

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