document.write( "Question 900632: You invested $12,000 in two accounts paying 6% and 8% annual interest, respectively. If the total interest earned for the year was $880, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #546101 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x+y=12000, \n" ); document.write( "0.06*x+0.08*y=880 \n" ); document.write( "x=12000-y \n" ); document.write( "0.06*(12000-y)+0.08*y=880 \n" ); document.write( "720-0.06y+0.08*y=880 \n" ); document.write( "0.02*y=160 \n" ); document.write( "y=8000 at 8% \n" ); document.write( "x=12000-y \n" ); document.write( "x=4000 at 6% \n" ); document.write( "check \n" ); document.write( "0.06*4000+0.08*8000=880 \n" ); document.write( "240+640=880 \n" ); document.write( "880=880 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |