document.write( "Question 900632: You invested $12,000 in two accounts paying 6% and 8% annual interest, respectively. If the total interest earned for the year was $880, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #546101 by richwmiller(17219)\"\" \"About 
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x+y=12000,
\n" ); document.write( "0.06*x+0.08*y=880
\n" ); document.write( "x=12000-y
\n" ); document.write( "0.06*(12000-y)+0.08*y=880
\n" ); document.write( "720-0.06y+0.08*y=880
\n" ); document.write( "0.02*y=160
\n" ); document.write( "y=8000 at 8%
\n" ); document.write( "x=12000-y
\n" ); document.write( "x=4000 at 6%
\n" ); document.write( "check
\n" ); document.write( "0.06*4000+0.08*8000=880
\n" ); document.write( "240+640=880
\n" ); document.write( "880=880
\n" ); document.write( "ok
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