document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=900740>Question 900740</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find  two consecutive integers such that the sum of three-fifths of the first and one-fourth of the second is 13. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546095 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the two consecutive numbers be x & x+1<BR>\n" );
document.write( "(3/5)x +(1/4)(x+1) =13\r<BR>\n" );
document.write( "\n" );
document.write( "LCM of denominator is 20<BR>\n" );
document.write( "multiply equation by 20\r<BR>\n" );
document.write( "\n" );
document.write( "12x+5(x+1) =20*13\r<BR>\n" );
document.write( "\n" );
document.write( "12x+5x+5=260\r<BR>\n" );
document.write( "\n" );
document.write( "17x=260-5\r<BR>\n" );
document.write( "\n" );
document.write( "17x=255<BR>\n" );
document.write( "/17<BR>\n" );
document.write( "x=15\r<BR>\n" );
document.write( "\n" );
document.write( "the numbers are 15 & 16 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );