document.write( "Question 900632: You invested $12,000 in two accounts paying 6% and 8% annual interest, respectively. If the total interest earned for the year was $880, how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #546063 by mananth(16946) $\"\"$ $\"About$

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Part I 8.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 6.00% per annum ------------ Amount invested = y
\n" ); document.write( " 12000
\n" ); document.write( "Interest----- 880.00
\n" ); document.write( "
\n" ); document.write( "Part I 8.00% per annum ---x
\n" ); document.write( "Part II 6.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 12000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "8.00% x + 6.00% y= 880
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8 x + 6 y= 88000.00 --------2
\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
\n" ); document.write( "-8 x -8 y= -96000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -8000
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 4000
\n" ); document.write( "Part I 8.00% $ 8000
\n" ); document.write( "Part II 6.00% $ 4000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "8000 --------- 8.00% ------- 640.00
\n" ); document.write( "4000 ------------- 6.00% ------- 240.00
\n" ); document.write( "Total -------------------- 880.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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