document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1685>Question 1685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I am trying to solve this Linear Equation System by using the substitution method:\r<BR>\n" );
document.write( "\n" );
document.write( "-x+3y=-1<BR>\n" );
document.write( "x-2y=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546 by </B><A HREF=/tutors/aboutme.mpl?userid=ichudov><B>ichudov(507)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ichudov><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ichudov><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can rewrite the second equation as saying\r<BR>\n" );
document.write( "\n" );
document.write( "x=6+2y\r<BR>\n" );
document.write( "\n" );
document.write( "then replace -(x) in the first equation with -(6+2y):\r<BR>\n" );
document.write( "\n" );
document.write( "-(6+2y)+3y=-1\r<BR>\n" );
document.write( "\n" );
document.write( "-6-2y+3y=-1\r<BR>\n" );
document.write( "\n" );
document.write( "-6+y=-1\r<BR>\n" );
document.write( "\n" );
document.write( "y=-1+6\r<BR>\n" );
document.write( "\n" );
document.write( "y=5\r<BR>\n" );
document.write( "\n" );
document.write( "Since x = 6+2y, x = 6+2*5 = 16. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );