document.write( "Question 900478: five times the larger of two consecutive odd integers is equal to one more than eight times the smaller. \n" ); document.write( "
Algebra.Com's Answer #545990 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
5A = 8B+1
\n" ); document.write( "A = B+2 (consecutive odd)
\n" ); document.write( "Substitute the value of A from the second equation into the first.
\n" ); document.write( "5(B+2) = 8B+1
\n" ); document.write( "Distribute
\n" ); document.write( "5B+10 = 8B+1
\n" ); document.write( "Subtract 1 from each side
\n" ); document.write( "5B + 9 = 8B
\n" ); document.write( "Subtract 5B from each side
\n" ); document.write( "9 = 3B
\n" ); document.write( "Divide each side by 3
\n" ); document.write( "3 = B
\n" ); document.write( "If the smaller number is 3, then the larger is 5.
\n" ); document.write( "
Prove it:
\n" ); document.write( "5*5 = 8*3 + 1
\n" ); document.write( "25 = 24 + 1
\n" ); document.write( "25 = 25
\n" ); document.write( "
\n" );