document.write( "Question 900478: five times the larger of two consecutive odd integers is equal to one more than eight times the smaller. \n" ); document.write( "
Algebra.Com's Answer #545990 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! 5A = 8B+1 \n" ); document.write( "A = B+2 (consecutive odd) \n" ); document.write( "Substitute the value of A from the second equation into the first. \n" ); document.write( "5(B+2) = 8B+1 \n" ); document.write( "Distribute \n" ); document.write( "5B+10 = 8B+1 \n" ); document.write( "Subtract 1 from each side \n" ); document.write( "5B + 9 = 8B \n" ); document.write( "Subtract 5B from each side \n" ); document.write( "9 = 3B \n" ); document.write( "Divide each side by 3 \n" ); document.write( "3 = B \n" ); document.write( "If the smaller number is 3, then the larger is 5. \n" ); document.write( " Prove it: \n" ); document.write( "5*5 = 8*3 + 1 \n" ); document.write( "25 = 24 + 1 \n" ); document.write( "25 = 25 \n" ); document.write( " |