document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=900321>Question 900321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 11 centimeters less than three times its width. Its area  is 42 square centimeters. Find the dimensions of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545964 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 3W-11<BR>\n" );
document.write( "L * W = A<BR>\n" );
document.write( "You can do this algebraically by substituting the value of L from the top equation into the bottom, but there's an easier way.<BR>\n" );
document.write( "One of the factor sets of 42 is 7/6.  You can tell right away that those are the correct numbers just by looking at the problem.  <BR>\n" );
document.write( "Prove it:<BR>\n" );
document.write( "7 = 3(6) - 11<BR>\n" );
document.write( "7 = 18-11<BR>\n" );
document.write( "7 = 7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );