document.write( "Question 900373: How many liters of a 50% acid solution must be mixed with a 20% acid solution to get 240 L of a 40% acid solution.
\n" ); document.write( "How many liters of a 50% acid solution must be used?
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Algebra.Com's Answer #545916 by richwmiller(17219)\"\" \"About 
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a+b=240,
\n" ); document.write( "0.5*a+0.2*b=0.4*240
\n" ); document.write( "a=240-b
\n" ); document.write( "0.5*(240-b)+0.2*b=96
\n" ); document.write( "120-0.5b+0.2*b=96
\n" ); document.write( "-0.3*b=-24
\n" ); document.write( "b=80
\n" ); document.write( "a=240-b
\n" ); document.write( "a=160 at 50% b=80 at 20%
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\n" ); document.write( "0.5*160+0.2*80=0.4*240
\n" ); document.write( "80+16=96
\n" ); document.write( "96=96
\n" ); document.write( "ok\r
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