document.write( "Question 900373: How many liters of a 50% acid solution must be mixed with a 20% acid solution to get 240 L of a 40% acid solution.
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document.write( "How many liters of a 50% acid solution must be used? \n" );
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Algebra.Com's Answer #545916 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! a+b=240, \n" ); document.write( "0.5*a+0.2*b=0.4*240 \n" ); document.write( "a=240-b \n" ); document.write( "0.5*(240-b)+0.2*b=96 \n" ); document.write( "120-0.5b+0.2*b=96 \n" ); document.write( "-0.3*b=-24 \n" ); document.write( "b=80 \n" ); document.write( "a=240-b \n" ); document.write( "a=160 at 50% b=80 at 20% \n" ); document.write( "check \n" ); document.write( "0.5*160+0.2*80=0.4*240 \n" ); document.write( "80+16=96 \n" ); document.write( "96=96 \n" ); document.write( "ok\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |