document.write( "Question 900373: How many liters of a 50% acid solution must be mixed with a 20% acid solution to get 240 L of a 40% acid solution.
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document.write( "How many liters of a 50% acid solution must be used? \n" );
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Algebra.Com's Answer #545915 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! .50x + .20(240L-x) = .40(240L) \n" ); document.write( " x = .20(240L)/.30, liters of a 50% acid solution \n" ); document.write( " |