document.write( "Question 900343: 51 coins. Some are 10$ coins and the rest are 20$ coins. The total of all the coins is 750$. How many of each does he have \n" ); document.write( "
Algebra.Com's Answer #545908 by richwmiller(17219) You can put this solution on YOUR website! x+y=51, \n" ); document.write( "10*x+20*y=750 \n" ); document.write( "x=51-y \n" ); document.write( "10*(51-y)+20*y=750 \n" ); document.write( "510-10y+20*y=750 \n" ); document.write( "10*y=240 \n" ); document.write( "y=24 \n" ); document.write( "x=51-y \n" ); document.write( "x=27 y=24 \n" ); document.write( "check \n" ); document.write( "27+24=51 \n" ); document.write( "10*x+20*y=750 \n" ); document.write( "10*27+20*24=750 \n" ); document.write( "270+480=750 \n" ); document.write( "750=750 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |