document.write( "Question 76047: A rug placed in room 12 m long and 9 m wide covers half the floor area and leaves a uniform strip of bare floor around the edges. What are the dimnesions of the rug? \n" ); document.write( "
Algebra.Com's Answer #54590 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! (12-2X)(9-2X)=(12*9)/2 \n" ); document.write( "108-18X-24X+4X^2=108/2 \n" ); document.write( "4X^2-42X+108=54 \n" ); document.write( "4X^2-42X+108-54=0 \n" ); document.write( "4X^2-42X+54=0 \n" ); document.write( "(X-9)(4X-6)=0 \n" ); document.write( "X-9=0 \n" ); document.write( "X=9 \n" ); document.write( "4X-6=0 \n" ); document.write( "4X=6 \n" ); document.write( "X=6/4 \n" ); document.write( "X=1.5 FEET IS THE WIDTH OF THE BARE FLOOR WHICH EQUALS 1/2 OF THE FLOOR AREA. \n" ); document.write( "PROOF \n" ); document.write( "(12-2*1.5)(9-2*1.5)=(12*9)/2 \n" ); document.write( "(12-3)(9-3)=108/2 \n" ); document.write( "9*6=54 \n" ); document.write( "54=54\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |