document.write( "Question 900266: Worker A can do a piece of work in 20 days. Workers A and B in 15 days.
\n" ); document.write( "They work together for 6 days and then A leaves. How long will B take to finish the work ?
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Algebra.Com's Answer #545852 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
1/a+1/b=1/x
\n" ); document.write( "1/20+1/b=1/15
\n" ); document.write( "3/20+1/b=4/60
\n" ); document.write( "1/b=1/60
\n" ); document.write( "b=60
\n" ); document.write( "check
\n" ); document.write( "1/20+1/60=1/15
\n" ); document.write( "3/60+1/60=4/60
\n" ); document.write( "4/60=4/60
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( "6/20+6/60+x/60=1
\n" ); document.write( "18/60+6/60+x/60=1
\n" ); document.write( "24/60+x/60=1
\n" ); document.write( "x/60=36/60=6/10
\n" ); document.write( "A and B did 24/60=.4 together
\n" ); document.write( "x=36 days for B to finish .6 of the job alone\r
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