document.write( "Question 900249: a man covers a certain distance on scooter.had he moved 3 kmph faster, he would have taken 40 min.less. if he had moved 2 kmph slower he would have taken 40 min.more .the distance is? \n" ); document.write( "
Algebra.Com's Answer #545851 by richwmiller(17219)\"\" \"About 
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r*t=d,
\n" ); document.write( "(r+3)*(t-40/60)=d,
\n" ); document.write( "(r-2)*(t+40/60)=d'
\n" ); document.write( "r*t=d,
\n" ); document.write( "(r+3)*(t-2/3)=d,
\n" ); document.write( "(r-2)*(t+2/3)=d
\n" ); document.write( "d = r* t,
\n" ); document.write( "d = 1/3 (r+3) (3*t-2),
\n" ); document.write( "d = 1/3 (r-2) (3*t+2)
\n" ); document.write( "d = r*t,
\n" ); document.write( "3d=3rt
\n" ); document.write( "3d = (r+3)*(3*t-2),
\n" ); document.write( "3d = (r-2)*(3*t+2)
\n" ); document.write( "3rt+9t-6-2r=3d
\n" ); document.write( "3rt-6t-4+2r=3d
\n" ); document.write( "9t-6-2r=0
\n" ); document.write( "-6t-4+2r=0
\n" ); document.write( "3t-10=0
\n" ); document.write( "3t=10
\n" ); document.write( "t=10/3\r
\n" ); document.write( "\n" ); document.write( "9*10/3-6-2r=0
\n" ); document.write( "30-6=2r
\n" ); document.write( "24=2r
\n" ); document.write( "r=12
\n" ); document.write( "d=12*10/3=40
\n" ); document.write( "distance is 40
\n" ); document.write( "d = 40, r = 12, t = 10/3
\n" ); document.write( "check
\n" ); document.write( "r*t=d,
\n" ); document.write( "12*10/3=40
\n" ); document.write( "(r+3)*(t-40/60)=d,
\n" ); document.write( "15*8/3=40
\n" ); document.write( "5*8=40
\n" ); document.write( "(r-2)*(t+40/60)=d
\n" ); document.write( "10*12/3=40
\n" ); document.write( "10*4=40
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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