document.write( "Question 900249: a man covers a certain distance on scooter.had he moved 3 kmph faster, he would have taken 40 min.less. if he had moved 2 kmph slower he would have taken 40 min.more .the distance is? \n" ); document.write( "
Algebra.Com's Answer #545848 by josgarithmetic(39800)\"\" \"About 
You can put this solution on YOUR website!
Be aware: I likely made a mistake in this, and have not successfully finished solving....\r
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\n" ); document.write( "\n" ); document.write( "RT=D uniform rates for travel\r
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\n" ); document.write( "\n" ); document.write( "_____________speed_______time______distance
\n" ); document.write( "IF FASTER____r+3_________t-2/3_____d=(r+3)(t-2/3)
\n" ); document.write( "IF SLOWER____r-2_________t+2/3_____d=(r-2)(t+2/3)
\n" ); document.write( "Rate Used____r____________t________d=rt\r
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\n" ); document.write( "\n" ); document.write( " A possible place in the analysis that someone could become stuck is to not recognize the very simple r*t=d, while each of these three variables is still unknown. \r
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\n" ); document.write( "\n" ); document.write( "(Removed the previous shown solution because of continuing mistakes while making corrections. See the following.)\r
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\n" ); document.write( "\n" ); document.write( "***CONTINUING WITH GOOD SOLUTION PROCESS---------------------------------------------------------\r
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\n" ); document.write( "\n" ); document.write( "FAST
\n" ); document.write( "\"rt%2B3t-%282%2F3%29r-2=d\"
\n" ); document.write( "\"rt%2B3t-%282%2F3%29r-2=rt\"
\n" ); document.write( "\"3t-%282%2F3%29r-2=0\"
\n" ); document.write( "\"9t-2r-6=0\"
\n" ); document.write( "\"highlight_green%289t-2r=6%29\"\r
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\n" ); document.write( "\n" ); document.write( "SLOW
\n" ); document.write( "\"rt-2t%2B%282%2F3%29r-4%2F3=d\"
\n" ); document.write( "\"-2t%2B%282%2F3%29r-4%2F3=0\"
\n" ); document.write( "\"2t-%282%2F3%29r%2B4%2F3=0\"
\n" ); document.write( "\"6t-2r%2B4=0\"
\n" ); document.write( "\"3t-r%2B2=0\"
\n" ); document.write( "\"highlight_green%283t-r=-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Start with Elimination Method to eliminate r.
\n" ); document.write( "Multiply SLOW equation by 2 and use subtraction, \"FAST-SLOW\".
\n" ); document.write( "\"9t-2r-%286t-2r%29=6-%28-4%29\"
\n" ); document.write( "\"9t-2r-6t%2B2r=10\"
\n" ); document.write( "\"3t=10\"
\n" ); document.write( "\"highlight%28t=10%2F3=3%261%2F3%29\", hours\r
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\n" ); document.write( "\n" ); document.write( "Use t in either equation, here being SLOW as the chosen equation, to find r.
\n" ); document.write( "\"-r%2B3%2810%2F3%29=-2\"
\n" ); document.write( "\"-r%2B10=-2\"
\n" ); document.write( "\"-r=-12\"
\n" ); document.write( "\"highlight%28r=12%29\", miles per hour\r
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\n" ); document.write( "\n" ); document.write( "The distance, according to r*t?
\n" ); document.write( "40 miles.
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