document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=900219>Question 900219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You invested $7000 in two accounts paying 7% and 6% annual interest, respectively. If the total interest earned for the year was $433, Let x denote the amount of money invested at 7%. Find an expression in terms of x for the amount invested at 6%. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545832 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545832\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=7000,<BR>\n" );
document.write( "0.07*x+0.06*y=433<BR>\n" );
document.write( "x=7000-y<BR>\n" );
document.write( "0.07*(7000-y)+0.06*y=433<BR>\n" );
document.write( "490-0.07y+0.06*y=433<BR>\n" );
document.write( "-0.01*y=-57<BR>\n" );
document.write( "y= 5700<BR>\n" );
document.write( "x=7000-y<BR>\n" );
document.write( "x=1300<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.07*1300+0.06*5700=433<BR>\n" );
document.write( "91+342=433<BR>\n" );
document.write( "433=433<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );