document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=900147>Question 900147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tom can finish a piece of work in 11 days. After he has worked for 2 days, Mike joins him and together they finish the work in 6 more days. In how many days could Mike finish the work by himself? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545816 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tom can finish a piece of work in 11 days. After he has worked for 2 days, Mike joins him and together they finish the work in 6 more days. In how many days could Mike finish the work by himself?<BR>\n" );
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document.write( "let x=number of days Mike could finish the work by himself<BR>\n" );
document.write( "1/x=Mike's work rate<BR>\n" );
document.write( "1/11=Tom's work rate<BR>\n" );
document.write( "6(1/x)+8(1/11)=1<BR>\n" );
document.write( "6/x+8/11=1<BR>\n" );
document.write( "6/x=1-8/11=11/11-8/11=3/11<BR>\n" );
document.write( "x/6=11/3<BR>\n" );
document.write( "3x=66<BR>\n" );
document.write( "x=22<BR>\n" );
document.write( "number of days Mike could finish the work by himself=22 </SPAN>\n" );
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