document.write( "Question 900095: How many liters of pure water should be mixed with an 8-L solution of 60% acid to produce a mixture that is 50% water? \n" ); document.write( "

Algebra.Com's Answer #545779 by richwmiller(17219) $\"\"$ $\"About$

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From the view of acid it is
\n" ); document.write( "since 100% water has 0% acid
\n" ); document.write( "0*x+.6*8=0.5(8+x)
\n" ); document.write( "4.8=4+.5x
\n" ); document.write( ".8=.5x
\n" ); document.write( ".8/.5=x
\n" ); document.write( "x=1.6 L
\n" ); document.write( "view of water
\n" ); document.write( "I changed from percent acid to percent non acid
\n" ); document.write( "60% acid means 40 % non acid
\n" ); document.write( "50% acid means 50 % non acid
\n" ); document.write( "Pure water is 100% non acid as a decimal 100%=1\r
\n" ); document.write( "\n" ); document.write( "1*x+0.4*8=0.5(8+x)
\n" ); document.write( "1*x+3.2=4+0.5x
\n" ); document.write( "1x-0.5x=4-3.2
\n" ); document.write( "0.5x=0.8
\n" ); document.write( "x=1.6 L Same answer!!!!
\n" ); document.write( "check
\n" ); document.write( "1*1.6+0.4*8=0.5(8+1.6)
\n" ); document.write( "1.6+3.2=0.5(9.6)
\n" ); document.write( "4.8=4.8
\n" ); document.write( "ok
\n" ); document.write( " \n" ); document.write( "

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