document.write( "Question 900095: How many liters of pure water should be mixed with an 8-L solution of 60% acid to produce a mixture that is 50% water? \n" ); document.write( "
Algebra.Com's Answer #545778 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of pure water should be mixed with an 8-L solution of 60% acid to produce a mixture that is 50% water? \n" ); document.write( "------------------ \n" ); document.write( "Equation: \n" ); document.write( "water + water = water \n" ); document.write( "1*x + 0.40*8 = 0.50(x+8) \n" ); document.write( "--------------- \n" ); document.write( "100x + 40*8 = 50x + 50*8 \n" ); document.write( "----- \n" ); document.write( "50x = 10*8 \n" ); document.write( "x = 8/5 = 1.6 litres (amt. of pure water to add) \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " |