document.write( "Question 900095: How many liters of pure water should be mixed with an 8-L solution of 60% acid to produce a mixture that is 50% water? \n" ); document.write( "
Algebra.Com's Answer #545778 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How many liters of pure water should be mixed with an 8-L solution of 60% acid to produce a mixture that is 50% water?
\n" ); document.write( "------------------
\n" ); document.write( "Equation:
\n" ); document.write( "water + water = water
\n" ); document.write( "1*x + 0.40*8 = 0.50(x+8)
\n" ); document.write( "---------------
\n" ); document.write( "100x + 40*8 = 50x + 50*8
\n" ); document.write( "-----
\n" ); document.write( "50x = 10*8
\n" ); document.write( "x = 8/5 = 1.6 litres (amt. of pure water to add)
\n" ); document.write( "----------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "---------------
\n" ); document.write( "
\n" );