document.write( "Question 900070: If 30 terms are inserted between 5 and 98 to form an arithmetic sequence, find their sum.
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document.write( "i think n is 30 t1 is 5 and tn is 98 but im not sure \n" );
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Algebra.Com's Answer #545772 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! n=32 \n" ); document.write( "a1=5 \n" ); document.write( "a32=98 \n" ); document.write( "S = ½(a1 + an)n \n" ); document.write( "S = ½(5 + 98)*32 \n" ); document.write( "S = 16*(103) \n" ); document.write( "S=1648\r \n" ); document.write( "\n" ); document.write( "We can now find \"d\" even though it wasn't requested \n" ); document.write( "S = ½(2a1 + (n-1)d)n \n" ); document.write( "1648 = ½(2*5 + (31)d)32 \n" ); document.write( "1648 = 16(2*5 + 31*d) \n" ); document.write( "1648 = 16(2*5 + 31*d) \n" ); document.write( "103=2*5 + 31*d \n" ); document.write( "103=10 + 31*d \n" ); document.write( "93=31d \n" ); document.write( "d=3 \n" ); document.write( "All 32 terms are : \n" ); document.write( " 5, 8,11,14,17,20,23,26,29,32, \n" ); document.write( "35,38,41,44,47,50,53,56,59,62, \n" ); document.write( "65,68,71,74,77,80,83,86,89,92, \n" ); document.write( "95,98\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |