document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75997>Question 75997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a)In function notation, write the following:  He takes a real number, multiplies it by 3, then adds 4, and then subtracts one-eighth of the result of multiplying the original number by -2.\r<BR>\n" );
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document.write( "Is it f(x) = 13/4 x + 4?\r<BR>\n" );
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document.write( "b)State the inverse function.\r<BR>\n" );
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document.write( "Is it f^-1(x) = 4/13 x - 16/13? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54572 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are right on the money with both answers. You can check the inverse by plugging in x=1 into the original equation and you'll get y=29/4. When you plug in x=29/4 into the inverse equation you'll get y=1 which is what you originally plugged in so it works. </SPAN>\n" );
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