document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=899873>Question 899873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 17cm. The first side is twice the length of the second side; the third side is 1cm less than 3 times the length of the side. What are the lengths of the side of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545636 by </B><A HREF=/tutors/aboutme.mpl?userid=suzanna18><B>suzanna18(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=suzanna18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second side would be x<BR>\n" );
document.write( "So the first side would be 2×x <BR>\n" );
document.write( "And the third is 3×x-1<BR>\n" );
document.write( "So the perimeter is 17= x + 2×x + 3×x-1<BR>\n" );
document.write( "16= 6×x<BR>\n" );
document.write( "16/6= 6×x/6<BR>\n" );
document.write( "x= 8/3<BR>\n" );
document.write( "2×x= 16/3<BR>\n" );
document.write( "3×x-1=7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );