document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=899874>Question 899874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A water tank can be emptied by using one pump for 5 hours. A second, smaller pump can empty the tank in 7 hours. If the larger pump is started at 1:00 P.M., how much time should pass until the smaller pump is started so that the tank will be emptied at 5:00 P.M.?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545635 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Since the larger pump can do the job in five hours and the whole job together will take on 4 hours the larger pump will do 4/5 of the job which leaves 1/5 for the smaller pump\r<BR>\n" );
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document.write( "4/5+x/7=1<BR>\n" );
document.write( "x/7=1/5<BR>\n" );
document.write( "x=7/5<BR>\n" );
document.write( "x=1.4 hours <BR>\n" );
document.write( "1 2/5 hours = 1 hour 24 minutes<BR>\n" );
document.write( "5:00-1:24<BR>\n" );
document.write( "4:60-1:24=3:36 pm <BR>\n" );
document.write( "Wait 2 hours and 36 minutes and turn on the smaller pump at 3:36 pm\r<BR>\n" );
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