document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=897391>Question 897391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sarah Meeham blends coffee for tasti delight. she needs to prepare 140 pounds of blended coffee beans selling for $4.50 per pund. She plans to do thid by blending together a hig-quality bean costing $5.50 per pound and a chaper bean at $3.50 per pound. To the nearest pound, find how much high-quality coffee bean and how much cheaper coffee bean she should blend </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545590 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545590\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+b=140,<BR>\n" );
document.write( "5.5*a+3.5*b=4.5*140<BR>\n" );
document.write( "a=140-b<BR>\n" );
document.write( "5.5*(140-b)+3.5*b=630<BR>\n" );
document.write( "770-5.5b+3.5*b=630<BR>\n" );
document.write( "-2*b=-140<BR>\n" );
document.write( "b=70<BR>\n" );
document.write( "a=140-b<BR>\n" );
document.write( "a=70 b=70<BR>\n" );
document.write( "check<BR>\n" );
document.write( "5.5*70+3.5*70=4.5*140<BR>\n" );
document.write( "385+245=630<BR>\n" );
document.write( "630=630<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );