document.write( "Question 899766: pam earns $468 per year in simpler interest by investing part of her money at 8% and the rest at 6%. if she invests $2000 more of her money at 8% than she invests at 6%, how much money did she invest at 8%? \n" ); document.write( "
Algebra.Com's Answer #545584 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "money invested at 6%.-----------x\r
\n" ); document.write( "\n" ); document.write( "money at 8% -------------- (x+2000)\r
\n" ); document.write( "\n" ); document.write( "pam earns $468 per year\r
\n" ); document.write( "\n" ); document.write( "8%(x+2000)+6%x = 468\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 100\r
\n" ); document.write( "\n" ); document.write( "8(x+2000) +6x = 46800\r
\n" ); document.write( "\n" ); document.write( "8x+16000+6x=46800\r
\n" ); document.write( "\n" ); document.write( "14x=46800-16000\r
\n" ); document.write( "\n" ); document.write( "14x=3800\r
\n" ); document.write( "\n" ); document.write( "x= 2000\r
\n" ); document.write( "\n" ); document.write( "money invested at 8% = 2000+2000=4000\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );