document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=899720>Question 899720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three consecutive odd integers are such that the square of the third integer is 65 less than the sum of the squares of the first two. One solution is -7, -5, and -3. Find three other consecutive odd integers that also satisfy the five conditions.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545577 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the integers be x,x+2,x+4\r<BR>\n" );
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document.write( "(x+4)^2= x^2+(x+2)^2-65\r<BR>\n" );
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document.write( "x^2+8x+16= x^2+x^2+4x+4-65\r<BR>\n" );
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document.write( "x^2-4x-77=0\r<BR>\n" );
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document.write( "x^2-11x+7x-77=0\r<BR>\n" );
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document.write( "x(x-11)+7(x-11)=0\r<BR>\n" );
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document.write( "(x-11)(x+7)=0\r<BR>\n" );
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document.write( "x= 11 Or -7\r<BR>\n" );
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document.write( "11,13,15 </SPAN>\n" );
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