document.write( "Question 899715: Solve the system of linear equations using the Gauss-Jordan elimination method.
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document.write( "x + y + z = 0
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document.write( "2x − y + z = 1
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document.write( "x + y − 2z = 2
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Algebra.Com's Answer #545565 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 1,1,1,0 \n" ); document.write( "2,-1,1,1 \n" ); document.write( "1,1,-2,2\r \n" ); document.write( "\n" ); document.write( "add down (-2) *row 1 to row 2 \n" ); document.write( "1,1,1,0 \n" ); document.write( "0,-3,-1,1 \n" ); document.write( "1,1,-2,2\r \n" ); document.write( "\n" ); document.write( "add down (-1) *row 1 to row 3 \n" ); document.write( "1,1,1,0 \n" ); document.write( "0,-3,-1,1 \n" ); document.write( "0,0,-3,2\r \n" ); document.write( "\n" ); document.write( "divide row 2 by -3 \n" ); document.write( "1,1,1,0 \n" ); document.write( "0,1,-1/-3,1/-3 \n" ); document.write( "0,0,-3,2\r \n" ); document.write( "\n" ); document.write( "add down (0) *row 2 to row 3 \n" ); document.write( "1,1,1,0 \n" ); document.write( "0,1,1/3,1/-3 \n" ); document.write( "0,0,-3,2\r \n" ); document.write( "\n" ); document.write( "divide row 3 by -3 \n" ); document.write( "1,1,1,0 \n" ); document.write( "0,1,1/3,1/-3 \n" ); document.write( "0,0,1,2/-3\r \n" ); document.write( "\n" ); document.write( "We now have the value for the last variable. \n" ); document.write( "We will work our way up and get the other solutions.\r \n" ); document.write( "\n" ); document.write( "add up (-1/3) *row 3 to row 2 \n" ); document.write( "1,1,1,0 \n" ); document.write( "0,1,0,-3/27 \n" ); document.write( "0,0,1,2/-3\r \n" ); document.write( "\n" ); document.write( "add up (-1) *row 3 to row 1 \n" ); document.write( "1,1,0,-2/-3 \n" ); document.write( "0,1,0,-1/9 \n" ); document.write( "0,0,1,2/-3\r \n" ); document.write( "\n" ); document.write( "add up (-1) *row 2 to row 1 \n" ); document.write( "1,0,0,21/27 \n" ); document.write( "0,1,0,-1/9 \n" ); document.write( "0,0,1,2/-3\r \n" ); document.write( "\n" ); document.write( "final \n" ); document.write( "1,0,0,7/9 \n" ); document.write( "0,1,0,-1/9 \n" ); document.write( "0,0,1,2/-3\r \n" ); document.write( "\n" ); document.write( "1,0,0,7/9 = 0.77777778 \n" ); document.write( "0,1,0,-1/9 = -0.11111111 \n" ); document.write( "0,0,1,-2/3 = -0.66666667 \n" ); document.write( "\"7/9\",\"-1/9\",\"-2/3\" \n" ); document.write( "(7/9,-1/9,-2/3) \n" ); document.write( " \n" ); document.write( " |