document.write( "Question 899640: A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1192 miles required 36 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city? \n" ); document.write( "
Algebra.Com's Answer #545559 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1192 miles required 36 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?
\n" ); document.write( "

\n" ); document.write( "Let amount of miles driven in the city be D
\n" ); document.write( "Then amount of miles driven on highway = 1,192 – D
\n" ); document.write( "Equation to be formed:
\n" ); document.write( "Miles driven in city, divided by advertised mpg in city, plus miles driven on highway,
\n" ); document.write( "divided by advertised mpg on highway, equals total gallons used. This is:
\n" ); document.write( "\"D%2F27+%2B+%281192+-+D%29%2F38+=+36\"
\n" ); document.write( "38D + 27(1,192 – D) = 36(27)(38) ------ Multiplying by LCD, 27(38)
\n" ); document.write( "38D + 32,184 – 27D = 36,936
\n" ); document.write( "38D – 27D = 36,936 – 32,184
\n" ); document.write( "11D = 4,752
\n" ); document.write( "D, or distance driven in the city = \"4752%2F11\", or \"highlight_green%28highlight_green%28432%29%29\" miles \n" ); document.write( "
\n" );