document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=899651>Question 899651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the measure of two suplementary angles is (4x-10)/(5x+1). Find the value of X. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545532 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A and B be the two angles that are supplementary.\r<BR>\n" );
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document.write( "Let A = 4x-10<BR>\n" );
document.write( "Let B = 5x+1\r<BR>\n" );
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document.write( "A+B = 180<BR>\n" );
document.write( "(4x-10)+(5x+1) = 180<BR>\n" );
document.write( "9x-9 = 180<BR>\n" );
document.write( "9(x-9) = 180<BR>\n" );
document.write( "x-9 = 180/9<BR>\n" );
document.write( "x-9 = 20<BR>\n" );
document.write( "x = 20+9<BR>\n" );
document.write( "x = 29\r<BR>\n" );
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document.write( "The value of x is x = 29<BR>\n" );
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