document.write( "Question 899622: If np ≥ 5 and nq ≥ 5, estimate P(more than 9) with n =14 and p=0.7 by using the normal distribution as an approximation to the binomial distribution; if np< 5 or nq<5, then state the normal approximation is not suitable.
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Algebra.Com's Answer #545525 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
n = 14
\n" ); document.write( "p = 0.7\r
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\n" ); document.write( "\n" ); document.write( "np = 14*0.7 = 9.8\r
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\n" ); document.write( "\n" ); document.write( "So np = 9.8 and np > 5\r
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\n" ); document.write( "\n" ); document.write( "n = 14
\n" ); document.write( "q = 1-p = 1-0.7 = 0.3
\n" ); document.write( "q = 0.3\r
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\n" ); document.write( "\n" ); document.write( "nq = 14*0.3 = 4.2
\n" ); document.write( "nq = 4.2\r
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\n" ); document.write( "\n" ); document.write( "nq > 5 is NOT true. Also nq is not equal to 5 either.\r
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\n" ); document.write( "\n" ); document.write( "nq < 5 which means that the normal approximation is not suitable\r
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\n" ); document.write( "\n" ); document.write( "You can use the binomial distribution formula (for pdf) and then add up the values from x = 10 to x = 14\r
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\n" ); document.write( "\n" ); document.write( "However, a much quicker way is to use a calculator like this one: http://stattrek.com/online-calculator/binomial.aspx\r
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\n" ); document.write( "\n" ); document.write( "and we get the answer\r
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\n" ); document.write( "\n" ); document.write( "P(X > 9) = 0.5842 (this is approximate)
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