document.write( "Question 899463: Olive wants to invest $15,000 with the goal of earning 10% interest. She wants to put some of the money in an investment that has been earning 7% a year and the rest of the money in an investment that typically earns 11% a year. How much money should be invested at 11% interest for Olive to obtain her goal of an overall 10% interest? \n" ); document.write( "
Algebra.Com's Answer #545432 by richwmiller(17219)\"\" \"About 
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x+y=15000,
\n" ); document.write( "0.07*x+0.11*y=1500
\n" ); document.write( "x=15000-y
\n" ); document.write( "0.07*(15000-y)+0.11*y=1500
\n" ); document.write( "1050.0-0.07y+0.11*y=1500
\n" ); document.write( "0.04*y=450.0
\n" ); document.write( "y=11250.0
\n" ); document.write( "x=15000-y
\n" ); document.write( "x=3750.0 y=11250.0
\n" ); document.write( "check
\n" ); document.write( "3750.0 +11250.0=15000
\n" ); document.write( "0.07*x+0.11*y=1500
\n" ); document.write( "0.07*3750.0+0.11*11250.0=1500
\n" ); document.write( "262.5+1237.5=1500
\n" ); document.write( "1500.0=1500
\n" ); document.write( "ok
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