document.write( "Question 899408: a chemist needs 22 liters of a 10% acid solution. how much of a 5% solution should be mixed with a 31% solution to get that? \n" ); document.write( "
Algebra.Com's Answer #545416 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! .31x + .05(22L-x) = .10(20L) \n" ); document.write( " x = .05(20L/.26 \n" ); document.write( " |