document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=899405>Question 899405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have the graph for the problem, i just need help on figuring out how they got the answer. The equation is (x-2)/3 - 5/(2y-4) =0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545379 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545379\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-2)/3 - 5/(2y-4) =0<BR>\n" );
document.write( "(2y-4)(x-2) - 15 = 0 |Multiplying thru by 3(2y-4) so as all denominators = 1<BR>\n" );
document.write( "2yx - 4x - 4y + 8 - 15 = 0<BR>\n" );
document.write( "2yx - 4x - 4y = 7<BR>\n" );
document.write( "2yx - 4y - 4x = 7<BR>\n" );
document.write( "2y(x-2) - 4x = 7<BR>\n" );
document.write( "  y = (4x+7)/2(x-2)<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );