document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75946>Question 75946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Without solving the inequality, what are the restrictions of x if log base 2^(x-1) - log base 2^(x+1) > 9? Please explain. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54534 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what are the restrictions of x if log base 2^(x-1) - log base 2^(x+1) > 9?<BR>\n" );
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document.write( "Rule to follows:<BR>\n" );
document.write( "To find log(x), x must be greater than zero.<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "For log(base 2) (x-1), x-1 >=0 ; x must be >=1<BR>\n" );
document.write( "For log(base 2) (x+1), x+1 >=0 ; x must be >=-1<BR>\n" );
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document.write( "Both of these conditions can be met as long as x>=1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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