document.write( "Question 899373: Julia drove to her holiday destination over a period of five days. On the first day she travels
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document.write( "a certain distance, on the second day she travels half that distance, on the third day a third of
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document.write( "that distance, on the fourth day one-quarter of the distance and on the fifth day one-fifth of the
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document.write( "distance. If her destination was 1000 km away write an equation and solve it to find how far she
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document.write( "travelled on the first day to the nearest kilometre. \n" );
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Algebra.Com's Answer #545333 by Theo(13342)![]() ![]() You can put this solution on YOUR website! 1000 = a + b + c + d + e\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = a \n" ); document.write( "b = a/2 \n" ); document.write( "c = b/3 = (a/2)/3 = a/6 \n" ); document.write( "d = c/4 = (a/6)/4 = a/24 \n" ); document.write( "e = d/5 = (a/24)/5 = a/120\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1000 = a + b + c + d + e becomes: \n" ); document.write( "1000 = a + a/2 + a/6 + a/24 + a/120\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by 120 and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "120 * 1000 = 120a + 60a + 20a + 5a + 1a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "120 * 1000 = 206a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 206 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "120 * 1000 / 206 = a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for a to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 582.5242...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 582.5242... \n" ); document.write( "b = a/2 = 291.2621... \n" ); document.write( "c = b/3 = 97.0873... \n" ); document.write( "d = c/4 = 24.2718... \n" ); document.write( "e = d/5 = 4.8543...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add them up and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sum(a,b,c,d,e) = 1000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that she traveled 583 kilometers on the first day. \n" ); document.write( " \n" ); document.write( " |