document.write( "Question 75901: Find an equation in x and y for the conic section with polar equation
\n" ); document.write( "r = 1/ 1+ cos(theta)
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Algebra.Com's Answer #54533 by stanbon(75887)\"\" \"About 
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Find an equation in x and y for the conic section with polar equation
\n" ); document.write( "r = 1/ 1+ cos(theta)
\n" ); document.write( "-------
\n" ); document.write( "Conversions formulas:
\n" ); document.write( "x=rcos(theta)
\n" ); document.write( "y=rsin(theta)
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\n" ); document.write( "r= x^2+y^2
\n" ); document.write( "EQUATION:
\n" ); document.write( "r = 1/(1+cos(theta)
\n" ); document.write( "r = 1/[1+(x/r)]
\n" ); document.write( "r = 1/[(r+x)/r]
\n" ); document.write( "r = r/(r+x)
\n" ); document.write( "1= 1/(r+x)
\n" ); document.write( "r+x=1
\n" ); document.write( "sqrt(x^2+y^2)+x=1
\n" ); document.write( "sqrt(x^2+y^2)=1-x
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x^2+y^2=1-2x+x^2
\n" ); document.write( "y^2=-2x+1
\n" ); document.write( "----------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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