document.write( "Question 899358: Juanita has 22000 to invest in two accounts that pay simple interest on an annual basis. one account pays 3% in simple interest, and other pays 6% simple interest how much would she have to invest in each account to earn a total interest of $810 after one year? \n" ); document.write( "
Algebra.Com's Answer #545329 by mananth(16946)\"\" \"About 
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Part I 3.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 6.00% per annum ------------ Amount invested = y
\n" ); document.write( " 22000
\n" ); document.write( "Interest----- 810.00
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\n" ); document.write( "Part I 3.00% per annum ---x
\n" ); document.write( "Part II 6.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 22000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "3.00% x + 6.00% y= 810
\n" ); document.write( "Multiply by 100
\n" ); document.write( "3 x + 6 y= 81000.00 --------2
\n" ); document.write( "Multiply (1) by -3
\n" ); document.write( "we get
\n" ); document.write( "-3 x -3 y= -66000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 3 y= 15000
\n" ); document.write( "divide by 3
\n" ); document.write( " y = 5000
\n" ); document.write( "Part I 3.00% $ 17000
\n" ); document.write( "Part II 6.00% $ 5000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "17000 --------- 3.00% ------- 510.00
\n" ); document.write( "5000 ------------- 6.00% ------- 300.00
\n" ); document.write( "Total -------------------- 810.00
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\n" ); document.write( "m.ananth@hotmail.ca
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