document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=899334>Question 899334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Derek sold walking sticks. Had he charged $10 extra for each stick he would have made $1,800. However, had he sold 10 more sticks at the original price he would have made $2,000. <BR>\n" );
document.write( "a) How many sticks did he sell?<BR>\n" );
document.write( "b) How much was each stick? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545315 by </B><A HREF=/tutors/aboutme.mpl?userid=hk><B>hk(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let us assume selling price of walking stick is 'x'and that he sold 'n'no of sticks.\r<BR>\n" );
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document.write( "from information given:\r<BR>\n" );
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document.write( "(x+10)*n=1800   ----- (I) and<BR>\n" );
document.write( "x*(n+10)= 2000   --------(II).\r<BR>\n" );
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document.write( "from I, xn+10n = 1800; and from II xn+10x = 2000<BR>\n" );
document.write( "solving the equations we get x = n+20.  Putting this back in equation I, and solving for n, we get n= 30 (no of sticks sold).  Hence price of stick ie. x is 50\r<BR>\n" );
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