document.write( "Question 899336: invested 10000$ for 1 year party at 7% and part 6.25% if she earned a total interest of 656.50$ how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #545309 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 7.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 6.25% per annum ------------ Amount invested = y \n" ); document.write( " 10000 \n" ); document.write( "Interest----- 656.50 \n" ); document.write( " \n" ); document.write( "Part I 7.00% per annum ---x \n" ); document.write( "Part II 6.25% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 10000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "7.00% x + 6.25% y= 656.5 \n" ); document.write( "Multiply by 100 \n" ); document.write( "7 x + 6.25 y= 65650.00 --------2 \n" ); document.write( "Multiply (1) by -7 \n" ); document.write( "we get \n" ); document.write( "-7 x -7 y= -70000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -0.75 y= -4350 \n" ); document.write( "divide by -0.75 \n" ); document.write( " y = 5800 \n" ); document.write( "Part I 7.00% $ 4200 \n" ); document.write( "Part II 6.25% $ 5800 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "4200 --------- 7.00% ------- 294.00 \n" ); document.write( "5800 ------------- 6.25% ------- 362.50 \n" ); document.write( "Total -------------------- 656.50 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |